A transverse wave propagates along a stretched string with a speed of 50 m/s. The amplitude of the wave is 0.2 m, and the wavelength is 0.6 m. Determine the frequency and period of the wave.
To find the frequency of the wave, we can use the equation:
v = λf
where:
v is the speed of the wave,
λ is the wavelength, and
f is the frequency.
Rearranging the equation, we have:
f = v/λ
Substituting the known values, we get:
f = 50 m/s / 0.6 m
Simplifying the expression, we obtain:
f ≈ 83.33 Hz
Therefore, the frequency of the wave is approximately 83.33 Hz.
To find the period of the wave, we can use the equation:
T = 1/f
where T is the period and f is the frequency.
Substituting the known value, we get:
T = 1 / 83.33 Hz
Calculating the expression, we obtain:
T ≈ 0.012 s
Therefore, the period of the wave is approximately 0.012 s.