Question:
A simple pendulum consists of a mass of 0.2 kg attached to a string of length 1.5 m. The pendulum is released from rest with an angle of 30 degrees. The motion of the pendulum can be approximated as simple harmonic motion.
Answer:
To calculate the period of the pendulum, we can use the formula:
where:
Given that L = 1.5 m and g = 9.8 m/s², we can substitute these values into the formula:
Calculating further:
Therefore, the period of the pendulum is:
(rounded to one decimal place)
To determine the maximum speed and maximum acceleration of the pendulum, we can use the formulas:
Maximum speed formula:
Maximum acceleration formula:
where:
Using the period calculated earlier (T ≈ 3.1 s), we can find :
Substituting the angle of 30 degrees, we find the amplitude using trigonometry:
Finally, substitute the obtained values into the formulas:
Maximum speed:
Maximum acceleration:
Evaluating these expressions will give the following results:
Maximum speed: (rounded to three decimal places)
Maximum acceleration: (rounded to three decimal places)
Explanation:
To find the period of the pendulum, we use the formula T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. Plugging in the given values L = 1.5 m and g = 9.8 m/s², we simplify and calculate the value of T.
To determine the maximum speed and maximum acceleration of the pendulum, we use the formulas v = A⋅ω and a = A⋅ω². First, we calculate the angular frequency ω by using the formula ω = 2π/T, where T is the period of the pendulum. With the calculated value of T, we substitute it into the formula and evaluate ω. Next, we find the amplitude A using the length of the pendulum and the given angle. Finally, we substitute the values of A and ω into the formulas for v and a, respectively, to obtain the maximum speed and maximum acceleration of the pendulum.