Question:

A block of copper with a mass of 0.5 kg is heated from an initial temperature of 25°C to a final temperature of 75°C. The specific heat capacity of copper is 385 J/kg·°C and its coefficient of linear expansion is 0.000016 °C^-1. Calculate the amount of heat absorbed by the copper block during this process. Assume the block undergoes uniform expansion.

Answer:

To calculate the amount of heat absorbed by the copper block, we need to consider the change in temperature and the specific heat capacity of copper. We can use the formula:

Q = mc∆T

where Q represents the amount of heat absorbed, m is the mass of the copper block, c is the specific heat capacity of copper, and ∆T is the change in temperature.

Given:

• Mass of copper block, m = 0.5 kg
• Specific heat capacity of copper, c = 385 J/kg·°C
• Initial temperature of copper block, T_initial = 25°C
• Final temperature of copper block, T_final = 75°C

First, let's determine the change in temperature:

∆T = T_final - T_initial ∆T = 75°C - 25°C ∆T = 50°C

Next, plug the values into the formula and solve for Q:

Q = mc∆T Q = (0.5 kg)(385 J/kg·°C)(50°C) Q = 9625 J

Therefore, the amount of heat absorbed by the copper block during this process is 9625 J.