Post

Created by @nathanedwards
 at November 1st 2023, 5:12:40 pm.

AP Physics 1 Exam Question

A block of mass mm is placed on a horizontal surface with a coefficient of friction μ\mu. It is connected to a hanging mass MM through a massless and frictionless pulley, as shown in the figure below.

block

  1. Determine the tension in the string connecting the block and the hanging mass.

Given:

  • Mass of the block: mm
  • Mass of the hanging mass: MM
  • Coefficient of friction between the block and the surface: μ\mu

(a) Assume the system is at rest and there is no acceleration. Identify the forces acting on the block and the hanging mass.

(b) Calculate the net force acting on each object.

(c) Write down the equation(s) that represent the equilibrium condition for the block and the hanging mass.

(d) Solve the equation(s) to find the tension in the string.

Answer

(a) For the block:

  • Gravitational force (mgmg) acting downwards.
  • Normal force (NN) exerted by the surface in the upward direction.
  • Frictional force (ff) opposing the block's motion.

For the hanging mass:

  • Gravitational force (MgMg) acting downwards.

(b) The net force on the block can be calculated by applying Newton's second law in the horizontal direction:

Net Forceblock=(ma)=Tensionf\text{Net Force}_{\text{block}} = (m \cdot a) = \text{Tension} - f

The net force on the hanging mass is simply its weight:

Net Forcehanging mass=(Mg)\text{Net Force}_{\text{hanging mass}} = (M \cdot g)(c)

For the block:

Net Forceblock=0    Tensionf=0\text{Net Force}_{\text{block}} = 0 \implies \text{Tension} - f = 0

For the hanging mass:

Net Forcehanging mass=0    Mg=0\text{Net Force}_{\text{hanging mass}} = 0 \implies M \cdot g = 0

(d) To find the tension in the string, we need to solve the equation from the block's equilibrium condition:

Tensionf=0\text{Tension} - f = 0

To find the frictional force ff, we can use the equation:

f=μNf = \mu \cdot N

Since the block is at rest, the vertical forces must balance:

N=mgN = mg

Substituting this value of NN into the equation for friction, we get:

f=μmgf = \mu \cdot mg

Now, we can substitute this value of ff into the equation for tension:

Tensionμmg=0\text{Tension} - \mu \cdot mg = 0

Solving for tension:

Tension=μmg\text{Tension} = \mu \cdot mg

Therefore, the tension in the string connecting the block and the hanging mass is μmg\mu \cdot mg.