Post

Created by @nathanedwards
 at October 31st 2023, 5:05:16 am.

Question:

Consider the following primitive data types in Java: int, double, char, and boolean. For each of the following code snippets, determine the output or result of the given expressions, and explain your reasoning step-by-step.

int num1 = 5;
int num2 = 3;
int result = num1 + num2 * 2;
System.out.println(result);
double num1 = 7.5;
double num2 = 2.5;
double result = num1 / num2;
System.out.println(result);
char letter1 = 'A';
char letter2 = 'B';
boolean result = (letter1 != letter2);
System.out.println(result);
int num1 = 10;
int num2 = 7;
boolean result = (num1 >= num2) && (num1 % num2 == 0);
System.out.println(result);

Answer:

  1. The output of this code snippet will be 11.

Step-by-step explanation:

  • num1 is initialized with the value 5, and num2 is initialized with the value 3.
  • The expression num2 * 2 evaluates to 6.
  • The expression num1 + num2 * 2 simplifies to 5 + 6, and the result of this expression is assigned to result.
  • Therefore, the value of result is 11, and when System.out.println() is called with result, it prints 11.
  1. The output of this code snippet will be 3.0.

Step-by-step explanation:

  • num1 is initialized with the value 7.5, and num2 is initialized with the value 2.5.
  • The expression num1 / num2 calculates the division of num1 by num2.
  • Since both num1 and num2 are of type double, the division result is also a double.
  • The division 7.5 / 2.5 evaluates to 3.0.
  • Therefore, the value of result is 3.0, and when System.out.println() is called with result, it prints 3.0.
  1. The output of this code snippet will be true.

Step-by-step explanation:

  • letter1 is initialized with the character 'A', and letter2 is initialized with the character 'B'.
  • The expression (letter1 != letter2) checks if letter1 is not equal to letter2.
  • Since 'A' is not equal to 'B', the expression evaluates to true.
  • Therefore, the value of result is true, and when System.out.println() is called with result, it prints true.
  1. The output of this code snippet will be false.

Step-by-step explanation:

  • num1 is initialized with the value 10, and num2 is initialized with the value 7.
  • The expression (num1 >= num2) checks if num1 is greater than or equal to num2.
  • Since 10 is greater than 7, the first part of the expression evaluates to true.
  • The expression (num1 % num2 == 0) checks if the remainder of num1 divided by num2 is equal to 0.
  • The remainder of 10 divided by 7 is 3, which is not equal to 0, so the second part of the expression evaluates to false.
  • The result of (num1 >= num2) && (num1 % num2 == 0) is true && false, which evaluates to false.
  • Therefore, the value of result is false, and when System.out.println() is called with result, it prints false.