Question:

Consider the following code snippet:

int a = 5, b = 10;
boolean x = false, y = true;

int result1 = (a++ * 5) + (++b);
int result2 = (x || y) ? (a + 2) : (b + 2);
int result3 = (a % b) * (b / a);
boolean result4 = (result1 == result2) && (result2 != result3);

System.out.println(result1);
System.out.println(result2);
System.out.println(result3);
System.out.println(result4);

What are the final values printed by the code? Show the step-by-step evaluation for each expression along with the outputs.

Explanation:

First, let's evaluate the code snippet step-by-step:

1. int result1 = (a++ * 5) + (++b);

   • a++ returns the original value of a and then increments it to 6.
   • ++b increments b to 11.
   • a++ * 5 evaluates to 5 * 5 = 25.
   • (5 * 5) + 11 evaluates to 36.
   • Therefore, result1 is 36.

2. int result2 = (x || y) ? (a + 2) : (b + 2);

   • The logical OR operator || evaluates to true if either x or y is true. Otherwise, it evaluates to false.
   • In this case, (x || y) evaluates to true since y is true.
   • Therefore, the output value will be (a + 2) which is 6 + 2 = 8.
   • Therefore, result2 is 8.

3. int result3 = (a % b) * (b / a);

   • a % b calculates the remainder of a divided by b which is 6 % 11 = 6.
   • b / a performs integer division of b by a which is 11 / 6 = 1.
   • Therefore, (6 * 1) evaluates to 6.
   • Therefore, result3 is 6.

4. boolean result4 = (result1 == result2) && (result2 != result3);

   • (result1 == result2) compares if result1 is equal to result2, which is 36 == 8, evaluates to false.
   • (result2 != result3) compares if result2 is not equal to result3, which is 8 != 6, evaluates to true.
   • Therefore, (false && true) evaluates to false.
   • Therefore, result4 is false.

Finally, the code will print the following values:

36
8
6
false

The output will be 36, 8, 6, and false on separate lines, respectively.

Therefore, the final values printed by the code are 36, 8, 6, and false.