Question:
Consider the equation of the circle given by the equation:
[x^2 + y^2 = r^2]
where r is a positive constant.
(a) Find dxdy using implicit differentiation.
(b) Find the derivative dx2d2y using implicit differentiation.
Answer:
(a) To find dxdy using implicit differentiation, we will differentiate both sides of the equation with respect to x and apply the chain rule.
Differentiating both sides of the equation x2+y2=r2 with respect to x, we get:
2x+2y⋅dxdy=0To isolate dxdy, we rearrange the equation as:
2y⋅dxdy=−2xDividing both sides of the equation by 2y, we find:
dxdy=−yxThus, the derivative of y with respect to x is given by −yx.
(b) To find the second derivative dx2d2y using implicit differentiation, we differentiate dxdy obtained in part (a) with respect to x.
Differentiating dxdy = −yx with respect to x, we get:
dx2d2y=dxd(−yx)=−y1⋅dxdySubstituting −yx for dxdy from part (a), we have:
dx2d2y=−y1⋅(−yx)=y2xThus, the second derivative of y with respect to x is given by y2x.