Sure, here's an AP Physics 1 exam question on the topic of work and energy:

Question:

A 2 kg block is initially at rest on a frictionless horizontal surface. It is then pulled by a force of 10 N at an angle of 30 degrees above the horizontal. The force is applied over a distance of 5 meters. Calculate the work done by the force and the final kinetic energy of the block.

Answer:

Step 1: Resolve the force into its horizontal and vertical components:

The horizontal component of the force, Fx = F * cos(30°) = 10 N * cos(30°) = 8.66 N The vertical component of the force, Fy = F * sin(30°) = 10 N * sin(30°) = 5 N

Step 2: Calculate the work done by the force:

W = F * d * cos(θ) = (8.66 N) * (5 m) * (cos 30°) = (8.66 N) * (5 m) * (0.866) ≈ 37.48 J

So, the work done by the force is approximately 37.48 Joules.

Step 3: Calculate the final kinetic energy of the block:

The work done by the force is equal to the change in kinetic energy of the block. Therefore, the work done by the force is equal to the final kinetic energy (K) of the block.

So, K = 37.48 J

Therefore, the final kinetic energy of the block is 37.48 Joules.

Thus, the work done by the force is approximately 37.48 Joules, and the final kinetic energy of the block is 37.48 Joules.

This question assesses the student’s understanding of work and energy concepts and their ability to apply trigonometric functions to calculate the work done by a force at an angle.