In the previous post, we learned about the concept of area under curves and its significance in real-world applications. Now, let's dive deeper and focus on finding the area under linear functions.
To find the area under a linear function in a specific interval, we can use definite integrals. The definite integral represents the signed area between the curve and the x-axis within the given interval.
Consider a linear function in the form of y = mx + c
, where m
represents the slope and c
represents the y-intercept. To find the area under the linear function, we need to integrate the function over the desired interval.
Let's find the area under the linear function y = 2x + 3
between x = 0
and x = 5
.
∫[0,5] (2x + 3) dx
To solve this integral, we can use the power rule of integration:
[(x^2)/2 + 3x] [0,5]
Substituting the upper and lower limits of integration:
[(5^2)/2 + 3(5)] - [(0^2)/2 + 3(0)]
=(25/2 + 15) - (0/2 + 0)
=(25/2 + 30/2)
=55/2
Hence, the area under the linear function y = 2x + 3
between x = 0
and x = 5
is 55/2
square units.
Finding the area under linear functions using definite integrals allows us to calculate the accumulated value of the function within a given interval. It is a powerful tool that finds applications in various fields of mathematics and real-world problem-solving.
Keep practicing and exploring the exciting world of area under curves! You're doing great!