Question:

A 2 kg object is initially at rest on a flat surface. A constant force of 8 N is applied to the object in the direction of motion and it moves a distance of 4 m. Calculate the work done on the object.

Answer:

The work done on an object is given by the equation:

Where F is the applied force, d is the distance traveled, and θ is the angle between the force and the direction of motion.

In this case, the force and the displacement are in the same direction, so θ = 0 degrees.

Given:

• Force (F) = 8 N
• Distance (d) = 4 m

Since the cosine of 0 degrees is 1, we can simplify the equation to:

Plugging in the values:

Therefore, the work done on the object is:

Hence, the work done on the object is 32 Joules (J).