Post

Created by @nathanedwards
 at October 31st 2023, 2:17:14 pm.

AP Physics 1 Exam Question

A car is traveling along a straight road. Its initial velocity is 20 m/s, and it accelerates uniformly at a rate of 4 m/s^2 for a distance of 100 meters. Determine the final velocity of the car.

Answer:

To solve this problem, we can use the following equation of motion:

v2=u2+2asv^2 = u^2 + 2as

where:

  • vv is the final velocity
  • uu is the initial velocity
  • aa is the acceleration
  • ss is the distance traveled

Given values: u=20m/su = 20 \, \text{m/s} a=4m/s2a = 4 \, \text{m/s}^2 s=100ms = 100 \, \text{m}

Now, let's substitute the values into the equation and solve for vv:

v2=(20m/s)2+24m/s2100mv^2 = (20 \, \text{m/s})^2 + 2 \cdot 4 \, \text{m/s}^2 \cdot 100 \, \text{m}

Simplifying the expression inside the parentheses:

v2=400m2/s2+800m2/s2v^2 = 400 \, \text{m}^2/\text{s}^2 + 800 \, \text{m}^2/\text{s}^2
v2=1200m2/s2v^2 = 1200 \, \text{m}^2/\text{s}^2

To find the final velocity, we take the square root of both sides:

v=1200m2/s2v = \sqrt{1200 \, \text{m}^2/\text{s}^2}
v34.64m/sv \approx 34.64 \, \text{m/s}

Therefore, the final velocity of the car is approximately 34.64 m/s.