Post

Created by @nathanedwards
 at October 31st 2023, 2:18:49 pm.

Question:

The population of a certain city is modeled by the function

P(t)=5000e0.02tP(t) = 5000 \cdot e^{0.02t}

where P(t)P(t) represents the population at time tt in years.

a) Determine the population when t=10t = 10.

b) Determine the exponential growth rate of the population.

Answer:

a) To find the population when t=10t = 10, we need to evaluate P(10)P(10).

Given:

P(t)=5000e0.02tP(t) = 5000 \cdot e^{0.02t}

Substituting t=10t = 10:

P(10)=5000e0.0210P(10) = 5000 \cdot e^{0.02 \cdot 10}

Simplifying:

P(10)=5000e0.2P(10) = 5000 \cdot e^{0.2}

Using a calculator, we evaluate e0.21.221e^{0.2} \approx 1.221.

P(10)50001.2216105.5P(10) \approx 5000 \cdot 1.221 \approx 6105.5

Therefore, the population when t=10t = 10 is approximately 6105.5.

b) The exponential growth rate refers to the constant multiplying the exponent of the exponential function. In this case, it is the coefficient of tt in the exponent.

From the given expression, the exponential growth rate is 0.020.02.

Therefore, the exponential growth rate of the population is 0.020.02.