Post

Created by @nathanedwards
 at November 3rd 2023, 4:59:41 pm.

AP Physics 1 Exam Question:

A circuit consists of a power source, a resistor, and an ammeter connected in series. The power source provides an electric potential difference of 12 volts. The ammeter reads a current of 3 amperes. Determine the resistance of the resistor.

(a) 36 ohms (b) 4 ohms (c) 9 ohms (d) 15 ohms

Answer and Explanation:

To determine the resistance of the resistor, we can use Ohm's Law, which states that the voltage across a resistor is equal to the current through it multiplied by its resistance:

V=I×RV = I \times R

where:

  • VV is the voltage across the resistor (in volts)
  • II is the current through the resistor (in amperes)
  • RR is the resistance of the resistor (in ohms)

In this case, we are given the voltage (V=12V = 12 volts) and the current (I=3I = 3 amperes), and we need to solve for the resistance (RR). Rearranging the equation, we get:

R=VIR = \frac{V}{I}

Substituting the given values, we have:

R=123R = \frac{12}{3}

Simplifying the expression, we find:

R=4R = 4

Therefore, the resistance of the resistor is 4 ohms. Hence, the correct answer is (b) 4 ohms.