Post

Created by @nathanedwards
 at November 4th 2023, 8:51:00 pm.

Question: A car is traveling along a straight road. The car starts from rest and reaches a final velocity of 40 m/s in a time of 8 seconds. Calculate the average acceleration of the car during this time interval.

(a) 5 m/s² (b) 10 m/s² (c) 15 m/s² (d) 20 m/s²

Answer:

We can calculate the average acceleration using the formula:

aavg=vfv0ta_{avg} = \frac{v_f - v_0}{t}

where:

  • aavga_{avg} is the average acceleration,
  • vfv_f is the final velocity,
  • v0v_0 is the initial velocity, and
  • tt is the time taken.

Given: vf=40m/sv_f = 40 \, \text{m/s}, v0=0m/sv_0 = 0 \, \text{m/s}, t=8st = 8 \, \text{s}.

Substituting the given values into the formula, we have:

aavg=40m/s0m/s8sa_{avg} = \frac{40 \, \text{m/s} - 0 \, \text{m/s}}{8 \, \text{s}}

Simplifying the expression further, we get:

aavg=40m/s8sa_{avg} = \frac{40 \, \text{m/s}}{8 \, \text{s}}

Dividing, we find:

aavg=5m/s2a_{avg} = 5 \, \text{m/s}^2

Therefore, the average acceleration of the car during this time interval is (a) 5 m/s².