Question:

Consider the following class definition:

public class Rectangle {
    private int width;
    private int height;

    public Rectangle(int w, int h) {
        width = w;
        height = h;
    }

    public int getWidth() {
        return width;
    }

    public int getHeight() {
        return height;
    }

    public int getArea() {
        return width * height;
    }

    public void scale(int factor) {
        width *= factor;
        height *= factor;
    }
}

You are given the Rectangle class above, which represents a rectangle shape. Using this class, you are required to write a program that does the following:

1. Create a Rectangle object named rect with width 5 and height 3.
2. Print the area of rect.
3. Scale rect by a factor of 2.
4. Print the updated area of rect.

Write the necessary code in the main method to complete the above tasks.

Explanation:

To complete the given tasks, the following code can be used:

public class Main {
    public static void main(String[] args) {
        Rectangle rect = new Rectangle(5, 3);
        
        // Printing the area of rect
        System.out.println("Area of rectangle: " + rect.getArea());
        
        // Scaling rect by a factor of 2
        rect.scale(2);
        
        // Printing the updated area of rect
        System.out.println("Updated area of rectangle: " + rect.getArea());
    }
}

In the main method, we create a Rectangle object named rect with width 5 and height 3. We then print the area of rect using the getArea() method. Next, we scale rect by a factor of 2 using the scale() method. Finally, we print the updated area of rect again using the getArea() method.

The output of the above code will be:

Area of rectangle: 15
Updated area of rectangle: 60

The area of the rectangle initially is 15 (width: 5, height: 3), and after scaling it by a factor of 2, the new area becomes 60 (new width: 10, new height: 6).