Question:

A 10-ohm resistor is connected in series with a 5-ohm resistor. A potential difference of 12 volts is applied across the circuit. Calculate the current flowing through the circuit and the power dissipated in each resistor.

Answer:

First, to calculate the total resistance of the circuit, we will add the resistances in series:

Total resistance (R_total) = 10 ohms + 5 ohms = 15 ohms

Next, we will use Ohm's law to calculate the total current flowing through the circuit:

Current (I) = Voltage (V) / Total resistance (R_total) I = 12 volts / 15 ohms I = 0.8 amperes

So, the current flowing through the circuit is 0.8 amperes.

Now we will calculate the power dissipated in each resistor using the formula:

Power (P) = Current (I) * Voltage (V)

For the 10-ohm resistor:

Power (P_10) = (0.8 A)^2 * 10 ohms P_10 = 6.4 watts

For the 5-ohm resistor:

Power (P_5) = (0.8 A)^2 * 5 ohms P_5 = 3.2 watts

Therefore, the power dissipated in the 10-ohm resistor is 6.4 watts and the power dissipated in the 5-ohm resistor is 3.2 watts.