AP Physics 1 Exam Question:
A wave is described by the equation:
y(x,t)=2sin((20πm−1)x−(100πs−1)t)where y is the displacement of the wave at position x and time t.
a) What is the wavelength of the wave?
b) What is the frequency of the wave?
c) What is the maximum displacement of the wave?
d) What is the speed of the wave?
Answer:
a) The wavelength of a wave is the distance between two consecutive points in the wave that are in the same phase. In the given equation, the coefficient of x is 20πm−1. Since 2π radians corresponds to one complete cycle, we can find the wavelength using the equation:
wavelength=wave number2πwhere wave number k=20πm−1.
wavelength=20πm−12π=101mTherefore, the wavelength of the wave is 101m.
b) The frequency of a wave is the number of complete cycles passing a point in one second. It is defined by the equation:
frequency=wavelengthspeed of the waveThe speed of the wave is the coefficient of t in the given equation, which is 100πs−1.
frequency=101m100πs−1=1000HzTherefore, the frequency of the wave is 1000Hz.
c) The maximum displacement of the wave is the amplitude, which is the coefficient of the sine function in the given equation. In this case, the maximum displacement is 2.
Therefore, the maximum displacement of the wave is 2m.
d) The speed of a wave is given by the equation:
speed of the wave=wavelength×frequencyUsing the values we calculated earlier, we have:
speed of the wave=(101m)×(1000Hz)=100m/sTherefore, the speed of the wave is 100m/s.