Question:
Consider the following code snippet:
public static void main(String[] args) {
try {
String str = null;
System.out.println(str.length());
} catch (NullPointerException e) {
System.out.println("NullPointerException occurred!");
} finally {
System.out.println("Finally block executed!");
}
}
Explain what will happen when this code is executed. Discuss the purpose of the try-catch blocks and the order in which the statements will be executed. Clearly explain the role of the finally
block in the code.
Answer:
When the provided code is executed, the following will happen:
main
method will be called, and the execution will enter the try block.NullPointerException
will occur when str.length()
is called because str
is assigned a null
value.System.out.println("NullPointerException occurred!");
will be executed, printing the message "NullPointerException occurred!" to the console.System.out.println("Finally block executed!");
will be executed, printing the message "Finally block executed!" to the console.The purpose of the try-catch blocks in this code is to handle any potential exceptions that may occur during runtime. By enclosing the potentially problematic code within a try block and providing a catch block with an appropriate exception type, the program can gracefully handle the exception and prevent it from causing a program termination. In this case, the catch block catches the NullPointerException
which occurs when trying to call str.length()
, preventing it from propagating and causing the program to crash.
The finally block, on the other hand, is used to guarantee that certain code is executed regardless of whether an exception occurred or not. In this example, the finally block includes a statement to print the "Finally block executed!" message. This block will always be executed, even if an exception occurs and the catch block is executed. Its purpose is to provide a way to ensure that certain cleanup or resource release tasks are performed, regardless of exceptional conditions.