Post

Created by @nathanedwards
 at November 1st 2023, 5:05:25 am.

Question:

Find the derivative of the following function:

f(x)=5x2+exln(x)+sin(x)f(x) = 5x^2 + e^x - \ln(x) + \sin(x)

Answer:

To find the derivative of the function, we will differentiate each term separately and then add them together.

  1. Differentiating the term 5x25x^2:

The general rule for differentiating a power of xx is to bring down the exponent as a coefficient and then decrease the exponent by 1. Applying this rule, we get:

ddx(5x2)=52x21\frac{d}{dx}(5x^2) = 5 \cdot 2x^{2-1}
ddx(5x2)=10x\frac{d}{dx}(5x^2) = 10x
  1. Differentiating the term exe^x:

The derivative of exe^x with respect to xx is simply exe^x.

ddx(ex)=ex\frac{d}{dx}(e^x) = e^x

  1. Differentiating the term ln(x)\ln(x):

The derivative of ln(x)\ln(x) can be found using the chain rule. The derivative of ln(u)\ln(u) with respect to uu, where uu is a function of xx, is given by 1ududx\frac{1}{u} \cdot \frac{du}{dx}.

In this case, u=xu = x, so dudx=1\frac{du}{dx} = 1. Applying the chain rule, we have:

ddx(ln(x))=1x1\frac{d}{dx}(\ln(x)) = \frac{1}{x} \cdot 1
ddx(ln(x))=1x\frac{d}{dx}(\ln(x)) = \frac{1}{x}
  1. Differentiating the term sin(x)\sin(x):

The derivative of sin(x)\sin(x) with respect to xx is cos(x)\cos(x).

ddx(sin(x))=cos(x)\frac{d}{dx}(\sin(x)) = \cos(x)

Now, adding all the derivatives together, we obtain:

ddx(5x2+exln(x)+sin(x))=10x+ex1x+cos(x)\frac{d}{dx}(5x^2 + e^x - \ln(x) + \sin(x)) = 10x + e^x - \frac{1}{x} + \cos(x)

Therefore, the derivative of the function f(x)=5x2+exln(x)+sin(x)f(x) = 5x^2 + e^x - \ln(x) + \sin(x) is 10x+ex1x+cos(x)10x + e^x - \frac{1}{x} + \cos(x).


Note: This problem assumes a basic knowledge of differentiation rules for each type of function.