Question:
Consider the function
f(x)=x−2x2+3x+5
- Determine the limit of f(x) as x approaches positive infinity.
- Determine the limit of f(x) as x approaches negative infinity.
- Determine whether the function f(x) has a horizontal asymptote. If so, find its equation.
Show all your work and justify your answers.
Answer:
- To find the limit of f(x) as x approaches positive infinity, we consider the behavior of the function as x becomes large. We divide the numerator and denominator of f(x) by the highest power of x to simplify the expression:
f(x)=x−2x2+3x+5=x/x−2/xx2/x+3x/x+5/x=1−x2x+3+x5As x approaches infinity, both x5 and x2 approach zero. Therefore, the expression simplifies to:
f(x)=x+3Thus, the limit of f(x) as x approaches positive infinity is ∞.
- To find the limit of f(x) as x approaches negative infinity, we once again divide the numerator and denominator of f(x) by the highest power of x:
f(x)=x−2x2+3x+5=x/x−2/xx2/x+3x/x+5/x=1−x2x+3+x5As x approaches negative infinity, both x5 and x2 approach zero. So, the expression simplifies to:
f(x)=x+3The limit of f(x) as x approaches negative infinity is −∞.
- To determine whether f(x) has a horizontal asymptote, we examine the limit of f(x) as x approaches positive infinity and as x approaches negative infinity.
From the previous parts, we found that as x approaches positive infinity, f(x) approaches infinity, and as x approaches negative infinity, f(x) approaches negative infinity. Since these limits are different, f(x) does not have a horizontal asymptote.
Hence, the function f(x) does not have a horizontal asymptote.