Post

Created by @nathanedwards
 at November 4th 2023, 6:30:40 pm.

Question:

Consider the function

f(x)=x2+3x+5x2f(x) = \frac{x^2 + 3x + 5}{x-2}
  1. Determine the limit of f(x)f(x) as xx approaches positive infinity.
  2. Determine the limit of f(x)f(x) as xx approaches negative infinity.
  3. Determine whether the function f(x)f(x) has a horizontal asymptote. If so, find its equation.

Show all your work and justify your answers.

Answer:

  1. To find the limit of f(x)f(x) as xx approaches positive infinity, we consider the behavior of the function as xx becomes large. We divide the numerator and denominator of f(x)f(x) by the highest power of xx to simplify the expression:
f(x)=x2+3x+5x2=x2/x+3x/x+5/xx/x2/x=x+3+5x12xf(x) = \frac{x^2 + 3x + 5}{x-2} = \frac{x^2/x + 3x/x + 5/x}{x/x - 2/x} = \frac{x + 3 + \frac{5}{x}}{1 - \frac{2}{x}}

As xx approaches infinity, both 5x\frac{5}{x} and 2x\frac{2}{x} approach zero. Therefore, the expression simplifies to:

f(x)=x+3f(x) = x + 3

Thus, the limit of f(x)f(x) as xx approaches positive infinity is \boxed{\infty}.

  1. To find the limit of f(x)f(x) as xx approaches negative infinity, we once again divide the numerator and denominator of f(x)f(x) by the highest power of xx:
f(x)=x2+3x+5x2=x2/x+3x/x+5/xx/x2/x=x+3+5x12xf(x) = \frac{x^2 + 3x + 5}{x-2} = \frac{x^2/x + 3x/x + 5/x}{x/x - 2/x} = \frac{x + 3 + \frac{5}{x}}{1 - \frac{2}{x}}

As xx approaches negative infinity, both 5x\frac{5}{x} and 2x\frac{2}{x} approach zero. So, the expression simplifies to:

f(x)=x+3f(x) = x + 3

The limit of f(x)f(x) as xx approaches negative infinity is \boxed{-\infty}.

  1. To determine whether f(x)f(x) has a horizontal asymptote, we examine the limit of f(x)f(x) as xx approaches positive infinity and as xx approaches negative infinity.

From the previous parts, we found that as xx approaches positive infinity, f(x)f(x) approaches infinity, and as xx approaches negative infinity, f(x)f(x) approaches negative infinity. Since these limits are different, f(x)f(x) does not have a horizontal asymptote.

Hence, the function f(x)f(x) does not have a horizontal asymptote.