Post

Created by @nathanedwards
 at November 4th 2023, 10:04:13 pm.

Question:

A car initially at rest accelerates uniformly at 2 m/s² for a distance of 10 meters. Calculate the final velocity of the car.

a) 2 m/s b) 4 m/s c) 6 m/s d) 8 m/s

Answer:

The equation relating displacement, initial velocity, final velocity, acceleration, and time is:

vf2=vi2+2aΔx v_f^2 = v_i^2 + 2a \Delta x

Given: Initial velocity, vi=0v_i = 0 (as the car is initially at rest), Acceleration, a=2m/s2a = 2 \, \text{m/s}^2, Displacement, Δx=10m\Delta x = 10 \, \text{m}.

Substituting these values into the equation:

vf2=02+2(2)(10) v_f^2 = 0^2 + 2(2)(10)
vf2=40 v_f^2 = 40

Taking the square root of both sides:

vf=40m/s6.32m/s v_f = \sqrt{40} \, \text{m/s} \approx 6.32 \, \text{m/s}

Therefore, the final velocity of the car is approximately 6.32 m/s.

The correct answer is c) 6 m/s.