Implicit Differentiation Exam Question
Consider the equation:
x3+y3−3xy+1=0
- Use implicit differentiation to find dxdy in terms of x and y.
Solution:
To find dxdy using implicit differentiation, we differentiate both sides of the given equation with respect to x.
dxd(x3+y3−3xy+1)=dxd(0)Differentiating each term separately, we get:
dxd(x3)+dxd(y3)−dxd(3xy)+dxd(1)=0Using the power rule, chain rule, and product rule, the derivatives are:
3x2+3y2dxdy−3(xdxdy+y)+0=0Now, we isolate dxdy term:
3y2dxdy−3xdxdy=−3x2+3yFactor out dxdy:
dxdy(3y2−3x)=−3x2+3yFinally, divide both sides by 3y2−3x to solve for dxdy:
dxdy=3y2−3x−3x2+3yHence, dxdy in terms of x and y is:
dxdy=3y2−3x−3x2+3yTherefore, the answer is:
[ \frac{{dy}}{{dx}} = \frac{{-3x^2 + 3y}}{{3y^2 - 3x}} ]