Consider the following code snippet:
public class DataTypesExample {
public static void main(String[] args) {
int a = 5, b = 2;
double c = 2.5, d = 1.8;
char e = 'A';
int sum1 = a + b;
double sum2 = c + d;
int sum3 = a + e;
System.out.println(sum1);
System.out.println(sum2);
System.out.println(sum3);
}
}
What will be the output of the above code?
A) 7 B) 4.3 C) 6 D) Compilation error
Explain your reasoning for the correct answer.
The correct answer is D) Compilation error.
In the given code, we can observe the following code segments:
int a = 5, b = 2;
double c = 2.5, d = 1.8;
char e = 'A';
int sum1 = a + b;
double sum2 = c + d;
int sum3 = a + e;
System.out.println(sum1);
System.out.println(sum2);
System.out.println(sum3);
int a = 5, b = 2;
- This line assigns the value 5
to the variable a
and 2
to the variable b
. Both a
and b
are of type int
, which is a primitive data type representing integers.
double c = 2.5, d = 1.8;
- This line assigns the value 2.5
to the variable c
and 1.8
to the variable d
. Both c
and d
are of type double
, which is a primitive data type representing floating-point numbers.
char e = 'A';
- This line assigns the character 'A'
to the variable e
. e
is of type char
, which is a primitive data type representing a single character.
int sum1 = a + b;
- This line performs the addition operation on int
type variables a
and b
, and stores the result in sum1
. Since both a
and b
are int
types, the result will be an int
.
double sum2 = c + d;
- This line performs the addition operation on double
type variables c
and d
, and stores the result in sum2
. Since both c
and d
are double
types, the result will be a double
.
int sum3 = a + e;
- This line attempts to perform the addition operation on int
type variable a
and char
type variable e
, and store the result in sum3
. However, adding a character to an integer is not a valid operation in Java, which will result in a compilation error.
System.out.println(sum1);
- This line prints the value of sum1
.
System.out.println(sum2);
- This line prints the value of sum2
.
System.out.println(sum3);
- This line tries to print the value of sum3
, but since it causes a compilation error, this line will never be executed.
Therefore, the output of the above code will be:
7
4.3
Compilation Error
Option D) Compilation error is the correct answer.