Post

Created by @nathanedwards
 at November 1st 2023, 12:10:48 am.

Question:

Consider the following code snippet:

public class DataTypesExample {
    public static void main(String[] args) {
        int a = 5, b = 2;
        double c = 2.5, d = 1.8;
        char e = 'A';
        
        int sum1 = a + b;
        double sum2 = c + d;
        int sum3 = a + e;
        
        System.out.println(sum1);
        System.out.println(sum2);
        System.out.println(sum3);
    }
}

What will be the output of the above code?

A) 7 B) 4.3 C) 6 D) Compilation error

Explain your reasoning for the correct answer.

Answer:

The correct answer is D) Compilation error.

In the given code, we can observe the following code segments:

int a = 5, b = 2;
double c = 2.5, d = 1.8;
char e = 'A';

int sum1 = a + b;
double sum2 = c + d;
int sum3 = a + e;

System.out.println(sum1);
System.out.println(sum2);
System.out.println(sum3);
  1. int a = 5, b = 2; - This line assigns the value 5 to the variable a and 2 to the variable b. Both a and b are of type int, which is a primitive data type representing integers.

  2. double c = 2.5, d = 1.8; - This line assigns the value 2.5 to the variable c and 1.8 to the variable d. Both c and d are of type double, which is a primitive data type representing floating-point numbers.

  3. char e = 'A'; - This line assigns the character 'A' to the variable e. e is of type char, which is a primitive data type representing a single character.

  4. int sum1 = a + b; - This line performs the addition operation on int type variables a and b, and stores the result in sum1. Since both a and b are int types, the result will be an int.

  5. double sum2 = c + d; - This line performs the addition operation on double type variables c and d, and stores the result in sum2. Since both c and d are double types, the result will be a double.

  6. int sum3 = a + e; - This line attempts to perform the addition operation on int type variable a and char type variable e, and store the result in sum3. However, adding a character to an integer is not a valid operation in Java, which will result in a compilation error.

  7. System.out.println(sum1); - This line prints the value of sum1.

  8. System.out.println(sum2); - This line prints the value of sum2.

  9. System.out.println(sum3); - This line tries to print the value of sum3, but since it causes a compilation error, this line will never be executed.

Therefore, the output of the above code will be:

7
4.3
Compilation Error

Option D) Compilation error is the correct answer.