Question:

A proton is placed in an electric field with a potential difference of 100 V between two points. Calculate the change in electric potential energy of the proton when it moves from the point with a potential of 20 V to the point with a potential of 80 V.

Given data: Initial potential (Vi) = 20 V Final potential (Vf) = 80 V Electric potential difference (ΔV) = Vf - Vi = 80 V - 20 V = 60 V Charge of a proton (q) = 1.6 x 10^-19 C

Answer: The change in electric potential energy (ΔPE) can be calculated using the formula:

ΔPE = q * ΔV

Where q is the charge of the proton and ΔV is the change in electric potential.

Plugging in the given values: ΔPE = (1.6 x 10^-19 C) * (60 V) ΔPE = 9.6 x 10^-18 J

Therefore, the change in electric potential energy of the proton when it moves from the point with a potential of 20 V to the point with a potential of 80 V is 9.6 x 10^-18 J.