Question:
Find the length of the curve defined by the equation y=x3−2x2+3x from x=0 to x=4.
Answer:
To find the length of a curve, we use the formula:
L=∫ab1+(dxdy)2dxwhere dxdy represents the derivative of y with respect to x.
First, let's find dxdy:
dxdy=3x2−4x+3Now, let's plug it into the formula for length:
L=∫041+(3x2−4x+3)2dxExpanding the expression inside the square root:
L=∫041+9x4−24x3+29x2−24x+9dxSimplifying the expression under the square root:
L=∫049x4−24x3+29x2−24x+10dxTo evaluate this integral, we can either use numerical methods or use a computer software. Evaluating the integral:
L≈16.051Therefore, the length of the curve defined by the equation y=x3−2x2+3x from x=0 to x=4 is approximately 16.051 units.