Question:
Find the limit algebraically:
x→3limx−3x2−5x+6Answer:
To find the limit algebraically, we can use direct substitution and simplify the expression. However, direct substitution gives us an indeterminate form (00) since both the numerator and denominator become zero when x=3.
To resolve this indeterminate form, we can factorize the numerator and then cancel out the common factor with the denominator. Let's factorize the numerator:
x2−5x+6=(x−2)(x−3)Now, we can rewrite the expression:
x→3limx−3x2−5x+6=x→3limx−3(x−2)(x−3)Notice that the factor (x−3) appears in both the numerator and the denominator. We can cancel out this common factor:
x→3lim(x−2)Now we can substitute x=3 into the expression:
x→3lim(x−2)=3−2Therefore, the limit algebraically is:
x→3limx−3x2−5x+6=1