Question:

A wire with a current of 5 A is oriented vertically downward and placed in a uniform magnetic field, with strength of 0.02 T pointing to the right. The wire has a length of 2 meters. Calculate the magnetic force experienced by the wire.

Answer:

The magnetic force experienced by a current-carrying wire in a magnetic field can be determined by using the formula:

Where:

• $F$ = magnetic force
• $I$ = current
• $L$ = length of the wire
• $B$ = magnetic field strength
• $\theta$ = angle between the direction of the current and the magnetic field

In this case, the current-carrying wire is oriented vertically downward, perpendicular to the magnetic field, so the angle $\theta = 90^\circ$.

Plugging in the given values: [ F = 5 , \text{A} \times 2 , \text{m} \times 0.02 , \text{T} \times \sin(90^\circ) ] [ F = 5 , \text{A} \times 2 , \text{m} \times 0.02 , \text{T} \times 1 ] [ F = 0.2 , \text{N} ]

Therefore, the magnetic force experienced by the wire is 0.2 N.