Post

Created by @nathanedwards
 at December 2nd 2023, 8:10:55 pm.

Question:

A car starts from rest and travels in a straight line with a constant acceleration of 2 m/s^2. After 5 seconds, what is the displacement of the car?

Answer:

To find the displacement of the car, we can use the equation:

s=ut+12at2 s = ut + \frac{1}{2}at^2

Where:

  • s s = displacement
  • u u = initial velocity (in this case, the car starts from rest, so u=0 u = 0 )
  • a a = acceleration
  • t t = time

Plugging in the given values:

  • u=0 u = 0
  • a=2m/s2 a = 2 \, m/s^2
  • t=5s t = 5 \, s

We get:

s=(0)(5)+12(2)(5)2 s = (0)(5) + \frac{1}{2}(2)(5)^2
s=0+12(2)(25) s = 0 + \frac{1}{2}(2)(25)
s=0+25 s = 0 + 25
s=25m s = 25 \, m

Therefore, after 5 seconds, the displacement of the car is 25 meters.