Post

Created by @nathanedwards
 at November 1st 2023, 1:15:16 am.

Question:

A light beam approaches a glass surface with an incident angle of 30°. The refractive index of the glass is 1.5. Determine the angle of refraction when the light beam enters the glass. Use Snell's law to solve this problem.

Solution:

Given: Incident angle (θ₁) = 30°, Refractive index of glass (n) = 1.5.

According to Snell's law,

n1sin(θ1)=n2sin(θ2) n₁ \sin(θ₁) = n₂ \sin(θ₂)

where n₁ and θ₁ are the refractive index and incident angle before the boundary, and n₂ and θ₂ are the refractive index and angle after the boundary.

We need to find θ₂, the angle of refraction when the light beam enters the glass.

Step 1: Substitute the given values into Snell's law equation:

1×sin(30°)=1.5×sin(θ2) 1 \times \sin(30°) = 1.5 \times \sin(θ₂)

Step 2: Solve for θ₂:

sin(θ2)=sin(30°)1.5 \sin(θ₂) = \frac{{\sin(30°)}}{{1.5}}
sin(θ2)=0.51.5 \sin(θ₂) = \frac{{0.5}}{1.5}

Step 3: Use a calculator to find the inverse sine (sin^(-1)) of the value obtained in Step 2 to find θ₂:

θ2=sin1(0.51.5)19.47° θ₂ = \sin^{-1}\left(\frac{{0.5}}{1.5}\right) \approx 19.47°

Therefore, the angle of refraction when the light beam enters the glass is approximately 19.47°.