Question:
Consider the following Java code segment:
public class DivisionCalculator {
public static int divideNumbers(int dividend, int divisor) {
if (divisor == 0) {
throw new ArithmeticException("Divisor cannot be zero");
}
return dividend / divisor;
}
public static void main(String[] args) {
int num1 = 10;
int num2 = 0;
try {
int result = divideNumbers(num1, num2);
System.out.println("Result of division: " + result);
} catch (ArithmeticException e) {
System.out.println("An exception occurred: " + e.getMessage());
}
}
}
Assuming the code segment is implemented correctly, what will be the output of running the program?
A. Result of division: 0
B. An exception occurred: Divisor cannot be zero
C. An exception occurred: / by zero
D. The program terminates abruptly
Explain your reasoning for selecting the correct option.
Answer:
The correct option is B. An exception occurred: Divisor cannot be zero.
The code segment begins by defining a class DivisionCalculator
with a method divideNumbers
which takes two integer arguments (dividend
and divisor
) and returns their division quotient. Inside the method, there is an if
condition to check if the divisor
is equal to zero. If it is, the method throws an ArithmeticException
with the message "Divisor cannot be zero".
In the main
method, two variables num1
and num2
are initialized with the values 10
and 0
, respectively. Then, within a try
block, the divideNumbers
method is called with num1
and num2
as arguments and the result is stored in result
variable. The statement System.out.println("Result of division: " + result);
is executed if no exception occurs.
Considering that the divisor
is indeed equal to zero in this case, the ArithmeticException
will be thrown, and the program will proceed to the catch
block. The catch block will print the message "An exception occurred: Divisor cannot be zero" using e.getMessage()
, where e
represents the caught ArithmeticException
object.
Thus, the output of running the program will be B. An exception occurred: Divisor cannot be zero.