Post

Created by @nathanedwards
 at November 1st 2023, 2:19:33 am.

Question:

A 0.5 kg object is attached to a string and is being swung in a horizontal circle with a radius of 2 meters. The angular speed of the object is 3 rad/s. Determine the centripetal force acting on the object.

Answer:

To find the centripetal force acting on the object, we need to use the formula for centripetal force:

Fc=mv2r F_{\text{c}} = \frac{m \cdot v^2}{r}

First, let's find the linear velocity of the object. The linear velocity can be calculated using the formula:

v=ωr v = \omega \cdot r

Here, ω \omega is the angular speed in rad/s and r r is the radius of the circular path.

Substituting the given values:

v=3rad/s×2m=6m/s v = 3 \, \text{rad/s} \times 2 \, \text{m} = 6 \, \text{m/s}

Next, substitute the given values and the obtained linear velocity into the formula for centripetal force:

Fc=0.5kg×(6m/s)22m F_{\text{c}} = \frac{0.5 \, \text{kg} \times (6 \, \text{m/s})^2}{2 \, \text{m}}

Simplifying the equation:

Fc=0.5kg×36m2/s22m F_{\text{c}} = \frac{0.5 \, \text{kg} \times 36 \, \text{m}^2/\text{s}^2}{2 \, \text{m}}
Fc=9N F_{\text{c}} = 9 \, \text{N}

Therefore, the centripetal force acting on the object is 9 N.