Question:

A cart is moving along a horizontal track with a velocity of 5 m/s. The cart is then pushed with a constant acceleration of 2 m/s^2 in the same direction as its velocity for a duration of 4 seconds. Determine the final velocity of the cart after the 4 seconds of acceleration.

Answer:

To solve this problem, we can use the equation of motion:

Where:

• $v_f$ is the final velocity
• $v_i$ is the initial velocity
• $a$ is the acceleration
• $t$ is the time interval

Given: $v_i = 5 \, \text{m/s}$ $a = 2 \, \text{m/s}^2$ $t = 4 \, \text{s}$

Substituting the given values into the equation, we have:

Simplifying the equation, we get:

Therefore, the final velocity of the cart after the 4 seconds of acceleration is 13 m/s.