Post

Created by @nathanedwards
 at October 31st 2023, 3:16:22 pm.

Question:

Find the limit algebraically:

limx3x29x3\lim_{x \to 3} \frac{x^2 - 9}{x - 3}

Explanation:

To find the limit, we can try direct substitution. Plugging in x=3x = 3 gives us:

32933\frac{3^2 - 9}{3 - 3}

However, this expression is of the form 00\frac{0}{0} which is undefined.

To proceed, we can simplify the expression by factoring the numerator:

limx3(x3)(x+3)x3\lim_{x \to 3} \frac{(x - 3)(x + 3)}{x - 3}

Notice that the term (x3)(x - 3) appears in both the numerator and denominator and can be canceled out:

limx3(x3)(x+3)x3\lim_{x \to 3} \frac{\cancel{(x - 3)}(x + 3)}{\cancel{x - 3}}

Leaving us with:

limx3(x+3)\lim_{x \to 3} (x + 3)

Now, we can evaluate the limit by direct substitution since the denominator no longer causes an undefined expression:

limx3(x+3)=3+3=6\lim_{x \to 3} (x + 3) = 3 + 3 = 6

Thus, the limit of the given expression as xx approaches 3 is 6.

Answer:

The limit,

limx3x29x3\lim_{x \to 3} \frac{x^2 - 9}{x - 3}
, is equal to 6.