Question:
Find the limit algebraically:
x→3limx−3x2−9Explanation:
To find the limit, we can try direct substitution. Plugging in x=3 gives us:
3−332−9However, this expression is of the form 00 which is undefined.
To proceed, we can simplify the expression by factoring the numerator:
x→3limx−3(x−3)(x+3)Notice that the term (x−3) appears in both the numerator and denominator and can be canceled out:
x→3limx−3(x−3)(x+3)Leaving us with:
x→3lim(x+3)Now, we can evaluate the limit by direct substitution since the denominator no longer causes an undefined expression:
x→3lim(x+3)=3+3=6Thus, the limit of the given expression as x approaches 3 is 6.
Answer:
The limit, x→3limx−3x2−9, is equal to 6.