Post

Created by @nathanedwards
 at November 3rd 2023, 2:08:08 am.

Question:

A certain nuclear reaction results in the formation of an alpha particle (α\alpha) and an unknown nuclear species XX. The alpha particle has a mass of 6.646×10276.646 \times 10^{-27} kg and a charge of 2e2e, where ee is the elementary charge. The unknown nuclear species XX has a mass of 4.014×1034.014 \times 10^{-3} kg and a charge of 3e3e.

If this reaction follows the general nuclear equation a+Ab+Xa + A \rightarrow b + X, where aa represents an alpha particle, AA represents the parent nucleus, bb represents the daughter nucleus, and XX represents the unknown nuclear species, determine the following:

a) The charge of the daughter bb nucleus. b) The mass of the daughter bb nucleus. c) The energy released during this nuclear reaction. d) Whether this nuclear reaction is an exothermic or endothermic process.

Given:

  • Elementary charge e=1.602×1019e = 1.602 \times 10^{-19} C
  • Speed of light c=2.998×108c = 2.998 \times 10^8 m/s

Answer:

a) The charge of the daughter bb nucleus can be determined using the principle of conservation of charge. In the reaction, the alpha particle (α\alpha) has a charge of 2e2e and the unknown nuclear species (XX) has a charge of 3e3e. Therefore, the total initial charge must be equal to the total final charge.

Initial charge = Charge of α\alpha particle + Charge of AA nucleus
Final charge = Charge of XX species + Charge of bb nucleus

Since the alpha particle (α\alpha) and the unknown nuclear species (XX) represent the initial and final charges respectively, we can write the equation as:

2e+Charge of A=3e+Charge of b2e + Charge\ of\ A = 3e + Charge\ of\ b

Rearranging the equation, we find:

Charge of bb nucleus = Charge of AA nucleus - ee

Substituting the values, we get:

Charge of bb nucleus = 3ee3e - e
Charge of bb nucleus = 2e2e

The charge of the daughter bb nucleus is 2e2e.

b) The mass of the daughter bb nucleus can be determined using the principle of conservation of mass. In the reaction, the alpha particle (α\alpha) has a mass of 6.646×10276.646 \times 10^{-27} kg and the unknown nuclear species (XX) has a mass of 4.014×1034.014 \times 10^{-3} kg. Therefore, the total initial mass must be equal to the total final mass.

Initial mass = Mass of α\alpha particle + Mass of AA nucleus
Final mass = Mass of XX species + Mass of bb nucleus

Since the alpha particle (α\alpha) and the unknown nuclear species (XX) represent the initial and final masses respectively, we can write the equation as:

6.646×10276.646 \times 10^{-27} kg + Mass of AA = 4.014×1034.014 \times 10^{-3} kg + Mass of bb

Rearranging the equation, we find:

Mass of bb nucleus = Mass of AA nucleus + 4.014×1034.014 \times 10^{-3} kg - 6.646×10276.646 \times 10^{-27} kg

Substituting the values, we get:

Mass of bb nucleus = 4.014×1034.014 \times 10^{-3} kg - 6.646×10276.646 \times 10^{-27} kg
Mass of bb nucleus 4.014×103\approx 4.014 \times 10^{-3} kg

The mass of the daughter bb nucleus is approximately 4.014×1034.014 \times 10^{-3} kg.

c) The energy released during this nuclear reaction can be determined using Einstein's mass-energy equivalence principle, E=mc2E = mc^2, where EE represents the energy released, mm represents the mass change, and cc represents the speed of light.

The mass change can be calculated as:

Mass change = Mass of α\alpha particle + Mass of AA nucleus - Mass of XX species - Mass of bb nucleus

Substituting the given values, we get:

Mass change = 6.646×10276.646 \times 10^{-27} kg + Mass of AA nucleus - 4.014×1034.014 \times 10^{-3} kg - 4.014×1034.014 \times 10^{-3} kg

Simplifying the equation, we find:

Mass change = 6.646×10276.646 \times 10^{-27} kg + Mass of AA nucleus - 8.028×1038.028 \times 10^{-3} kg

By considering the mass-energy equivalence principle, the energy released can be calculated as:

Energy released = Mass change ×\times Speed of light2^2

Substituting the values, we get:

Energy released = (Mass change) ×\times (2.998×108)2(2.998 \times 10^8)^2 J

However, since the mass of AA nucleus and the specific reaction are not provided, we cannot determine the exact energy released without those values.

d) To determine whether this nuclear reaction is exothermic or endothermic, we need to compare the final energy to the initial energy. If the final energy is lower than the initial energy, it is an exothermic process. If the final energy is higher than the initial energy, it is an endothermic process. However, without the specific values for the energy released from part c, we cannot make a definitive determination.