AP Physics 1 Exam Question: Nuclear Physics
A radioactive isotope, Technetium-99m (
a) How many
b) Determine the decay constant (λ) for
c) Calculate the activity of the
d) What will be the activity of the sample after 36.12 hours?
e) Explain why the activity does not depend on the size of the radioactive sample.
Provide answers with step-by-step detailed explanations.
Answer:
a) The number of remaining atoms after a certain time can be calculated using the decay equation:
N(t) = N₀ × (1/2)^(t/T)
where N₀ is the initial number of atoms, t is the time elapsed, and T is the half-life.
Given: N₀ = 256, t = 24.04 hours, T = 6.01 hours
Plugging in the values:
N(t) = 256 × (1/2)^(24.04/6.01)
N(t) = 256 × (1/2)^(4)
N(t) = 256 × 1/16
N(t) = 16
Therefore, 16
b) The decay constant (λ) can be determined using the formula:
λ = ln(2) / T where T is the half-life.
Given: T = 6.01 hours
λ = ln(2) / 6.01
λ ≈ 0.1156 hours⁻¹
Therefore, the decay constant (λ) for
c) The activity at a certain time is given by:
A(t) = λ × N(t)
where A(t) is the activity and N(t) is the number of remaining atoms.
Given: λ = 0.1156 hours⁻¹, t = 12.03 hours
Using the result from part (a), N(t) = 16
A(t) = 0.1156 × 16
A(t) ≈ 1.85 Bq (becquerels)
Therefore, the activity of the
d) Using the same formula as in part (c):
Given: λ = 0.1156 hours⁻¹, t = 36.12 hours
Using the result from part (a), N(t) = 16
A(t) = 0.1156 × 16
A(t) ≈ 1.85 Bq (becquerels)
Therefore, the activity of the
e) The activity of a radioactive sample does not depend on its size because activity is defined as the number of decay events per unit time (measured in becquerels). It is a property of the radioactive substance itself and is independent of the quantity of the substance present. Therefore, even if the size of the sample changes, the activity remains the same as long as the radioactive substance remains the same. The rate of decay depends on the decay constant, which remains constant for a specific radioactive isotope.