Post

Created by @nathanedwards
 at October 31st 2023, 11:22:38 pm.

Question:

Find the limit algebraically:

limx2x3+3x2x4x3x+5\lim_{x \to \infty} \frac{2x^3 + 3x^2 - x}{4x^3 - x + 5}

Step-by-step Solution:

To find the limit of the given expression as xx approaches infinity, we can simplify the expression by dividing every term by the highest power of xx in the denominator.

Divide each term in the numerator and denominator by x3x^3:

limx2x3x3+3x2x3xx34x3x3xx3+5x3\lim_{x \to \infty} \frac{\frac{2x^3}{x^3} + \frac{3x^2}{x^3} - \frac{x}{x^3}}{\frac{4x^3}{x^3} - \frac{x}{x^3} + \frac{5}{x^3}}

Simplifying the expression, we get:

limx2+3x1x241x2+5x3\lim_{x \to \infty} \frac{2 + \frac{3}{x} - \frac{1}{x^2}}{4 - \frac{1}{x^2} + \frac{5}{x^3}}

As xx approaches infinity, all terms involving 1x\frac{1}{x} and 1x2\frac{1}{x^2} will tend to zero. We can ignore these terms in the numerator and denominator, yielding:

limx24\lim_{x \to \infty} \frac{2}{4}

Simplifying further, we have:

limx12\lim_{x \to \infty} \frac{1}{2}

Thus, the limit of the given expression as xx approaches infinity is 12\frac{1}{2}.